The NFL named Houston Texans DE J.J. Watt the AFC Defensive Player of the Week following his performance against the Jacksonville Jaguars on Sunday. Watt led the team with eight tackles (five solo), to go along with a single-game season-high 3.0 sacks, three tackles for loss, four quarterback hits, two passes defensed, one forced fumble and one fumble recovery in the Texans’ 30-6 victory.
It was Watt’s 21st career multi-sack game, the second-most of any player in the NFL over his first five seasons in league history, and his fifth career game with 3.0-or-more sacks. Watt’s 3.0 sacks on Sunday gave him an NFL-best 17.5 for the year, which marks his third career 15.0-sack season, the second-most in the NFL since 1982. Reggie White is the only other player to notch three 15.0-sack seasons in his first five years in the league.
Watt finished the 2015 season leading the NFL in sacks (17.5), tackles for loss (29) and quarterback hits (50). He leads the NFL in each of those categories since entering the league in 2011. The two-time Defensive Player of the Year also recorded 76 tackles (57 solo), eight passes defensed, three forced fumbles and one fumble recovery on the way to his third AFC South Division title in the last five years. His sack total ranks as the third-highest single-season mark in franchise history behind his 20.5 sacks in 2012 and 2014.
I think we've reached a point where the NFL should just announce the rare occasions when J.J. Watt DOESN'T win AFC Defensive Player of the Week. If the man doesn't win his third Defensive Player of the Year award in the next few weeks, we riot.
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